Sodium Thiosulphate And Hydrochloric Acid Coursework

I have done the pratical work and found that the rection was first order with respect to the thio and both first and zero order with respect to the acid, depending on the concentration.

Can anyone give me some help with the reaction mechanism as I cant come up with any ideas.

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Therefore the slowest runner (the slowest step in the reaction mechanism) will limit (hence the term "rate limiting step") the speed that the whole relay team can run.

No matter how fast the other runners are, they have to wait for the slow one and so it limits the overall speed and thus determines it, since most intermediate steps happen nearly instantaneously.The equation for this acid-catalysed reaction is as follows: S2O32−(aq) → SO32−(aq) S(s) Assuming Wiki to be a reliable source, this would explain why the reaction can be zero order with respect to the acid.This is the only step where the acid isn't involved, and is also known as the rate-determining step.cheers m8 Can you explain why the reaction is first order w.r.t.sodium thio is it to do with reaction kinetics, where if you double the conc of the reacants, there are more frequent collisions, hence the rate of reaction increases Sodium thiosulphate isn’t reacting with anything, so the number of collisions for that step can be ignored.H2O (aq)) SO2 (g) this would show that step 1 is the rate determining step cuz its the slowest step due to the sodium thiosulphate being decomposed and it also shows that: SO32-(aq) HSO3-(aq) H (aq) would be cancelled out so they are reaction intermediates, but does that mean that the concentration of H wouldn't have any affect on the reaction, because i have it as first order I try to explain the order of reaction more like a relay race.The intermediate steps run like a relay, one has to go before the other.The amount of HCl will affect the reaction at low concentrations because you need a certain amount of HCl to collide with the reactants in order for a reaction to occur.However there comes a point where you have enough HCl to collide with the reactants, and the only thing that's holding the reaction up is the above step, which is why the rate with respect to HCl becomes 0 order.Increase this number to 2000 thio molecules, 5% of that is 100 at the correct activation energy.More thio molecules at the correct activation energy required for decomposition will mean that you have more SO32−(aq) for the proceeding reactions.


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