If you're seeing this message, it means we're having trouble loading external resources on our website. So now what we can say is, is that the first four exams, I could either list out the first four exams that I took. So I know the sum of the first four exams is going to 4 times 84. I said after four exams, after four exams, I had an 84 average.
If you're behind a web filter, please make sure that the domains *.and *.are unblocked. Averages is probably a concept that you've already used before, maybe not in a mathematical way. And now I want to add the, what I get on the 5th exam, x. What do I have to get on that next exam to average an 88 in the class after 5 exams? If I said that there are 6 exams in the class, and the highest score I could get on an exam is 100, what is the highest average I can finish in the class if I were to really study hard and get 100 on the next 2 exams?
Example Find the mean of the following data set: 56, 35, 45, 67, 12, 24, 48, 55, 58, 30 $$\frac=$$ $$=\frac=43$$ $$The\: mean=43$$ The median is the number in an ordered set of data that is in the middle.
If we have a set of data with an odd number of data points then the median is the data point in the middle.
We know that the average after four exams, at four exams, is equal to 84.
Now let's make this a little bit more difficult. I don't know if if I gave myself enough space. I think you're now ready for the average module.
But people will talk in terms of, the average voter wants a politician to do this, or the average student in a class wants to get out early. So the average of these four numbers is equal to 7.25. And I'm going to divide that by all five exams. 440 equals 4 times 84, we just saw that, is 320 plus 16 is 336. Well, it turns out if you subtract 336 from both sides, you get x is equal to 104. Well, once again, what we'll want to do is assume we get 100 on the next 2 exams and then take the average. So we're going to have the average of 6, so in the denominator we're going to have 6.
So you're probably already familiar with the concept of an average. And then we have 10, I didn't have to do that decimal there, oh well. And that might make sense to you because 7.25 is someplace in between these numbers. So in other words, this number is the average of my first five exams. So unless you have a exam that has some bonus problems on it, it's probably impossible for you to get ah an 88 average in the class after just the next exam. The first four exams, the sum, as we already learned, is 4 exams times the 84 average. Plus, and there's going to be 2 more exams, right?
The second statistician also takes aim and shoots, but this time the bullet goes sailing past six inches too low.
The two statisticians then give one another high fives and exclaim, "Got him!